Quiz : Time Required to Heat Water

Rate this item
(34 votes)
11 September
File (s) are available for download. You must login to access the file(s).

This quiz is about heating time required to increase the temperature of water. Imagine that there are two containers filled with same mass of water. The initial temperature of water in Container A is 100C and that in Container B is 200C.

To simplify the problem, imagine that both the containers are insulated with perfect insulation, mean there is zero heat loss in the atmosphere during heating process. Both the containers are identical in all the aspects including shape, size, and material. The only difference is initial temperature of water insider the container.

 Quiz-Heating-Time-For-Water-Initial-Tempeature

Water in both the containers is heated with same heat source. It means, the rate of heat addition in both the containers is same. Water in container A is to be heated from 100C to 200C. Water in container B is to be heated from 200C to 300C. 

Quiz-Heating-Time-For-Water-Initial-delta-T

Question


With above conditions, answer the following question:

To increase the temperature of water (100C to 200C for container A, and 200C to 300C for container B), time required for heating will be

  1. Same for both the containers
  2. Container A will take more time than container B
  3. Container B will take more time than container A
  4. Insufficient data provided. Cannot be predicted.

 

How to post your answer ?


Post your answer as a comment at the bottom of this page. Login to your LearnCAx account or write your Name and Email ID so that we can publish the answer. Make sure to check “Notify me of follow-up comments” to receive notification about all the updates on this quiz.

Write your choice of answer from above four options. It is also expected (but not compulsory) that you should write the reason (or justification) for your answer. All the answers will be published on 18th September 2014. We will also post the correct answer with a justification.

 

Earn Reward Points


  1. Earn 1 point only for the correct choice without justification
  2. Earn 3 points for correct choice with justification
  3. Earn 5 points if you answer is selected as one of the best answer
  4. After looking at few answers, I am forced to add this. A correct choice which wrong justification will get 0 points

These reward points could be used to get discount on all our courses and projects.

 

Quiz Participation


Thanks for participating in the quiz. Looks like there are total 800 people seen this quiz (Rough data based on number of visitors). Out of 800 people, 13 people have answered the quiz. Congratulations to those who have answered the question. You already fall into elite group of 1.6 % people answering the question.

Following the analysis of answers given:

partipant-analysis

Total 13 reward points are given by LearnCAx to various participants. Those who have answered will receive a separate email notification about the reward points earned.

Best answer

The best answer selected is given by “Bruno”. Bruno writes:

“Container A will take more time then container B.
The time would only be the same if we could consider that the enthalpy variation was linear, which it isn't (although it almost is). But the enthalpy change from 20 to 30 C is slightly smaller than from 10 to 20, so heating container B from 20 to 30 should take a slightly smaller time.”

Read all the answers given in below comments. It was a great learning experience for us to read your answers. We are sure every visitor will also feel same.

Note: The reward points and best answer is selected by LearnCAx team after doing detailed analysis. By no means, we want to question anyone’s understanding about the physics. These quizzes are created just to share different views and have a fun!!

 

Answer by LearnCAx Team


The correct answer is

2: Container A will take more time than container B

Importance of assumptions

It is assumed that there is no heat loss from container to atmosphere. If we do not make this assumption, container B will have more heat loss as compared to container A. Without this assumption, this difference will play some role in deciding heating time.

It is assumed that rate of heat addition in both containers is same. Note that we are assuming the amount of heat addition is same. In case even if heat source is same, the rate of heat addition is decided by conductivity, viscosity (as this is natural convection). As we are assuming that rate of heat addition is same, mean no matter what happens inside the tank, the water inside tank is going to absorb the same amount of heat. So conductivity and viscosity is not playing any role in time required to increase the temperature.

Justification for our answer

With above assumptions true, the only factor deciding time required to increase the temperature is Cp (Specific Heat of Water). 

Heating time required:
= (Heat required for 100C temperature rise) / (Rate of heat addition)
= (m x Cp x ΔT) / (Rate of heat addition)

Where:

  • Rate of heat addition is same for both containers
  • m = Mass of water (Same for both containers)
  • ΔT = Temperature difference between initial and final temperature (100C for both containers)
  • Cp = Specific heat of water

As all the parameters are same, we need to check variation of Cp with respect to temperature.

Cp variation with temperature is non-linear. If we see the variation of Cp from 50C to 900C, Cp is decreasing with temperature with minimum value at 370C and then increasing. Following plot shows that variation.

Water-Cp-vs-temp-at-1-atm-pressure 

Lets look at Cp variation between 100C to 200C (for container A) and 200C to 300C (for container B). 

Water-Cp-vs-temp-at-1-atm-pressure-10-20-30-deg-c 

Above plot shows that Cp values for Container A temperature range (100C to 200C) is more that Cp values for Container B temperature range (200C to 300C). In order to estimate the actual heating time, we need to consider variation of Cp with respect to temperature (and hence with respect to time). So the calculations will be unsteady calculations. Even if we consider constant values (average of minimum and maximum), the average value Cp for container A is more than average value Cp for container B.

All above property variations are taken from National Institute of Standards and Technology. If you want to check property variation Click here. A text file containing property variations of water with respect to temperature is attached with this article. You can download that after logging with LearnCAx account.

Let’s do a sample calculation

Assume following values:

Heat addition rate = 3500 J/s (A typical heat addition rate of gas stove)
m = 1000 grams (Approximate weight of 1 litre water)
ΔT = 100C (Temperature difference for both containers)

Let’s calculate average value of Cp for Container A and Container B by using following chart:

Water-Cp-vs-temp-at-1-atm-pressure-10-20-30-deg-c-chart

Average Cp value for Container A = (4.1952 + 4.1841) / 2 = 4.1896 J/gK

Average Cp value for Container B = (4.1841 + 4.1798)) / 2 = 4.1819 J/gK

Heating time for container can be calculated using following equation:

Heating time required:
= (Heat required for 100C temperature rise) / (Rate of heat addition)
= (m x Cp x ΔT) / (Rate of heat addition)

Heating time for container A:
= (1000 x 4.1896 x 10) / (3500)
= 11.97 Seconds

Heating time for container B:
= (1000 x 4.1819 x 10) / (3500)
= 11.95 Seconds

So heating time for Container A is more than that of Container B (although this might not be signification for you ).

Important Note: Above results are valid only with the assumptions made. You may see some different results in reality. In reality when you heat water, the container is not perfectly insulated. So the heat loss rate will increase with increase in temperature. Viscosity and conductivity of water decrease with temperature and will have some impact on heating time.

Hope you enjoyed the quiz. A PDF copy of this quiz with answer is available for download. Login with your LearnCAx account or Create Account to access the download section given at top.


 

The Author

vijay-mali

Vijay is COO and Co-Founder of CCTech & LearnCAx. Vijay's major contribution in professional career is growing CCTech from team of two people to group of 30 technologists and now CCTech is a preferred partner to many engineering industries. At CCTech, Vijay look after business development for CFD division and a member of technical review committee.

Since beginning of Vijay's professional career, he has passion for education. At CCTech, he conceptualized a unique training program on CFD which was then taken by more than 500 students and most of them are now working as CFD analyst in industry. This program is now considered as benchmark for classroom training. The same passion caused birth of LearnCAx, an online education brand of CCTech. LearnCAx is first MOOC platform dedicated for CFD education.

Prior to CCTech, Vijay worked with ANSYS India (formerly Fluent India) in FloWizard development team. Vijay hold M.Tech. in Aerospace Engineering from IIT Bombay.


Share thisShare on FacebookShare on Google PlusShare on TwitterShare on LinkedIn
Read 3772 times
Quiz : Time Required to Heat Water - 5.0 out of 5 based on 34 votes

Latest from Vijay Mali

Related items

More in this category: « CCTech Launches LearnCAx

Add comment




Security code
Refresh

Comments  

 
0 walid 2014-09-12 05:35
the same time
Quote
 
 
0 HariKirupakar 2014-09-13 12:43
The correct answer is (2) i.e., Container A will take more time than container B.

Justification:
Q equals M*C*(det T). In both the cases the mass, increase in temperature and the operating conditions are same. C increases as temperature increases which means that more heat is required to raise the temperature of a unit mass of the water as temperature increases. Since the change in C is very minimal, we can expect the time difference also to to be small.

Note : This logic will hold good only for a temperature range of 20 deg C to 40 deg C because after 40 deg C, the value of C starts to decrease as temperature decreases
Quote
 
 
0 Jaime Penalva 2014-09-16 12:37
Container A will take more time than container B. Because density and specific heat decreases with temperature. In other words, from 10 to 20 C the product of density and specific heat is greater that from 20 to 30 C
Quote
 
 
0 Ahmedpet12 2014-09-17 15:07
because water molecules inside container B more active & highly thermal conductivity
Quote
 
 
0 archana t m 2014-09-17 21:45
If we assume that specific heat of water is constant(considering that the variation is very small), mass of water is same and so is the temperature difference, hence the heat required will be same in both case.
Quote
 
 
0 P.Premkumar 2014-09-18 17:07
Container A will take more time than container B
Quote
 

Browse Knowledge Base

Recommended By

Get Instant Updates

Subscribe to get instant updates about CFD courses, projects, blogs, webinars, software tutorials & CFD jobs

Search Knowledge Base

By Keyword

By Author

By Tag